straight line up part of graph #miles of titrant = #moles of analyte concentration and volume of titrant is then used to determine concentration of analyte
Frozen!
Frozen!
maximum buffering capacity pH = pKa
how do you calculate a buffer's pH
strong acid strong base equivalence point pH = 7 @ 25 C / 298 K
pH + pOH = 14 always!!
how to increase/decrease buffering capacity increasing/decreasing concentrations of buffer components, but keeping the ratios constant (if you don't it'll change the buffer capacity for either acid or base respectively)
solution that is resistant to a small pH change, it has to contain a weak acid or base pared with its conjugate salt(Na+, H3O-, etc...) and it creates neutral compounds, keeping pH relatively stable
Kw = 1.0 x 10^-14 at 25 C or 298 K
strong acid-weak base reaction if weak base is in excess --> a buffer --> Hendeson Hasselbalch equaiton if strong acid is in excess, the moles of excess acid are used to determine pH if acid and base are equimolar then the equilibrium concentrations are used to determine pH
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Frozen!
H2O pH is always... 7, could be acid (pH) or base (pOH)
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Boost!
in what range are buffers effective
weak acid-strong base reaction HA(aq) + OH- --> A-(aq) + H2O(L) if weak acid is in excess --> a buffer --> Hendeson Hasselbalch equaiton if strong base is in excess, the moles of excess hydroxide ions is used for pH if acid and base are equimolar then the equilibrium concentr
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14 always!!
Frozen!
Frozen!
maximum buffering capacity
how to increase/decrease buffering capacity increasing/decreasing concentrations of buffer components, but keeping the ratios constant (if you don't it'll change the buffer capacity for either acid or base respectively)
what is a buffer solution that is resistant to a small pH change, it has to contain a weak acid or base pared with its conjugate salt(Na+, H3O-, etc...) and it creates neutral compounds, keeping pH relatively stable
weak acid-strong base reaction HA(aq) + OH- --> A-(aq) + H2O(L) if weak acid is in excess --> a buffer --> Hendeson Hasselbalch equaiton if strong base is in excess, the moles of excess hydroxide ions is used for pH if acid and base are equimolar then the equilibrium concentr
straight line up part of graph #miles of titrant = #moles of analyte concentration and volume of titrant is then used to determine concentration of analyte
strong acid strong base equivalence point pH = 7 @ 25 C / 298 K
pH = pKa + log [A-]/[HA] ---> acids pOH = pKb + log [BH+]/[B] ---> bases the conjugate salt is on top, and the bottom is either the base or the acid assume there is a limiting and excess reagent (because it will contain either a strong acid or base)
1.0 x 10^-14 at 25 C or 298 K
Frozen!
Frozen!
H2O pH is always... 7, could be acid (pH) or base (pOH)
Boost!
Boost!
in what range are buffers effective within 1 pH of its pKa, up or down
if weak base is in excess --> a buffer --> Hendeson Hasselbalch equaiton if strong acid is in excess, the moles of excess acid are used to determine pH if acid and base are equimolar then the equilibrium concentrations are used to determine pH
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Incorrect!
Incorrect!
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